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炸群神器定海神针怎么下载(微信炸群超长文字专用定海神针代码)

 2023-05-17 11:17  来源:互联网  我来投稿

  许多微信用户在向微信官方反映,微信群里面出现了一群“炸群”的人,他们通过往微信群里面发送大量的符号代码,导致微信瞬间瘫痪,也就是所谓的“炸群”,实际上使用的便是定海神针,那么炸群神器定海神针怎么下载?本期全民创业网分享一份微信炸群超长文字专用定海神针代码

炸群是什么意思(定海神针刷屏神器5万字)

  一、炸群神器定海神针怎么下载

  留意微信群,这种微信群里经常发这些定海神针刷屏神器,在网上运气好也可下到。

  刷屏也叫作洗板(版),洗屏,广义指在网上论坛、留言版、BBS以及即时聊天室、网络游戏聊天系统(公频),弹幕视频网站等同一ID或少数ID短时间集中发送大量内容重复或高度相似的信息或在公共聊天区(如QQ群)等单次或多次发布足以超出屏幕的信息。

  二、微信炸群超长文字专用定海神针代码

  代码实现

  # -*- coding = utf-8 -*-

  # @Time : 2021/1/26 15:19

  # @Author : 陈良兴

  # @File : 微信表情包炸群.py

  # @Software : PyCharm

  # 运行程序 > 输入次数 > 回车 > 打开微信对话框 > 将鼠标放置在“发送”按钮处即可

  from pynput.keyboard import Controller as KB #控制键盘输入

  from pynput.mouse import Controller,Button #控制鼠标点击

  import time

  import random

  Wechat_expression = [

  "[微笑]","","[色]","[发呆]","","","","","[睡]","","[尴尬]",

  "","[调皮]","","[惊讶]","[难过]","[囧]","","","","[愉快]","",

  "[傲慢]","","[惊恐]","","[悠闲]","[咒骂]","[疑问]","","","","","[猪头]",

  "","","","","","[坏笑]","","","","",

  "[阴险]","[亲亲]","","[笑脸]","[生病]","[脸红]","[破涕为笑]","","[失望]","[无语]",

  "[嘿哈]","","","","","","[吃瓜]","","","[天啊]","[Emm]",

  "[社会社会]","[旺柴]","[好的]","","[哇]","","","[让我看看]","[叹气]","[苦涩]",

  "[裂开]","[嘴唇]","[爱心]","[心碎]","[拥抱]","","[弱]","","[胜利]","[抱拳]","[勾引]",

  "[拳头]","[OK]","[合十]","","[咖啡]","","","[凋谢]","[菜刀]","[便便]","",

  "","","[红包]","[發]","[福]","[跳跳]","[发抖]","[转圈]","","[庆祝]","[烟花]"

  ]

  #键盘控制函数

  def keyboardInput(string):

  keyboard = KB()

  keyboard.type(string)

  #鼠标控制函数

  def mouseClick():

  mouse = Controller()

  mouse.press(Button.left)

  mouse.release(Button.left)

  #响应函数

  def response(number):

  time.sleep(5) #延迟5s响应

  for i in range(number):

  sentence = random.choice(Wechat_expression)

  keyboardInput(sentence)

  mouseClick()

  time.sleep(0.4) #每条消息间隔0.4秒

  if __name__ == "__main__":

  while True:

  print("发动机已启动,随时可以出发!")

  Num = input("请输入轰炸次数:")

  if Num.isdigit():

  response(int(Num))

  print("报告长官,轰炸完毕,请求下一步作战计划!!!")

  else:

  print("输入错误,请重新输入一个整数!!!")

  #询问是否继续

  answer = input("是否执行下一次作战计划?(y 或者 n):")

  if answer == "y":

  print("继续轰炸!!!")

  continue

  if answer == "n":

  print("停止轰炸,给他们喘口气!!!")

  break

  else:

  print("输入错误,请输入“y”或者“n”!!!")

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